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> Opštinsko Takmičenje Iz Fizike 2007.

Laza_91
post Feb 11 2007, 02:42 PM
Post #61





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QUOTE(Cekaaa @ Feb 11 2007, 01:28 PM)
Uradio sam sve i sve mi je tacno, sem sto sam napravio racunsku gresku u 5-om. Resenja koja sam dobio:

1. 19.xxxxxxx125
2. 20m/s,20m/s
3.24s,288m
4.t(sqrt(5)-1)
5.v/((cos a) na kvadrat), i lepo dobijem 2v rezultat, medjutim napisem na kraju da je to 10km/h, a treba 40km/h  XD.gif  XD.gif  XD.gif
*



Auu:
1.19,00125m (Uzeo g=10m/s2)
2.20m/s,0 blink.gif znam da sam pogresio...
3.24s=16s+8s,288m
4.t=(sqrt(5)-1)/2 ,... s***** sam 1/2d na kraju , valjda će mi dati 20 poena(zadatak nosi 25p)
5. 40 km/h tongue.gif tongue.gif tongue.gif Nije mi postupak baš najbolji,ali....
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maxydelanoche
post Feb 11 2007, 02:44 PM
Post #62





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Ja mislim da cu imati 80, prva cetiri su mi tacna, a peti sam... A kako je lak zadatak nije normalno... Mislim, shvatila sam da je lak kad sam videla resenje. Ne mogu da verujem da mi takav nacin resavanja nije pao na pamet... Ali dobro. Prolaz, nadam se, nece biti iznad 80 smile.gif


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Iva
post Feb 11 2007, 02:47 PM
Post #63





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Sta ja da kazem za 3? ...


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Laza_91
post Feb 11 2007, 02:47 PM
Post #64





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Pa 5 i nije bio baš lak...Onako kako sam ja mislio da se radi...
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pyost
post Feb 11 2007, 02:47 PM
Post #65


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QUOTE
poyst jel mozes da postavis postupna resenja za 1, 3 i 4 zadatak za drugi razred sa sistemom bodovanja?


Ne znam sistem bodovanja, a mogu ukratko da opisem 1. i 3. - stvarno nemam strpljenja ponovo da ih radim.

1. Posmatramo sile koje deluju na svako telo. Na telo 1 deluje sila trenja i sila zatezanja 1. Na telo 2 deluje njegova tezina i sila zatezanja 2. Na osnovu toga na kotur deluje T1 na levo i T2 na dole. Sada posmatramo rotaciju kotura.

\alpha I = M_2-M_1

{{1}\over{2}}mr^2\alpha = T_2r-T_1r

{{1}\over{2}}ma=T_2-T_1

Osim ove formule, imamo i dve formule za kretanje oba tela. Kada se sve tri formule uzmu u obzir, lako se dobija ubrzanje, a posle i rad.

2. Posmatramo vrednosti pritisaka preko zadate formule.

p_1=b-aV_1

 \Delta V=V_2-V_1

p_2=b-aV_1-a \Delta V

p_1-p_2=a \Delta V

a={{p_1-p_2}\over{V_2-V_1}}

Zamenom u pocetnoj formuli se dobija i b, dok je dobijanje formule za T krajnje jednostavno.


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^_NiN0_^
post Feb 11 2007, 02:57 PM
Post #66


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Ja nisam dokazao da je 1/2ma=deltaT! XD.gif Nisam imao vremena , a znao sam !!! sleep.gif Ozbiljno


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pyost
post Feb 11 2007, 03:00 PM
Post #67


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Mislim da ti tu nece skidati bodove, to je ocigledno..


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Laza_91
post Feb 11 2007, 03:02 PM
Post #68





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e,koliko je proshle godine trebalo za prolazak na gradsko???

Svi mi kažu različito!!!
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Cekaaa
post Feb 11 2007, 03:10 PM
Post #69





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Koje je to jednostavno resenje za peti zadatak? Onaj kvadrat sam dobio iz nekih slicnosti trouglova i aproksimacija... tongue.gif
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^_NiN0_^
post Feb 11 2007, 03:10 PM
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44 poena. Zavisi sve kako drugi urade, postoji sansa da je ne prodjem sada
biggrin.gif biggrin.gif


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Puzzler
post Feb 11 2007, 03:13 PM
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Prvo da čestitam svima, super ste uradili, pretpostavljam... smile.gif
A ja ću sad malo odraditi taj peti da vidim... dry.gif


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Laza_91
post Feb 11 2007, 03:17 PM
Post #72





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KAD ĆE VIŠE REZULTATI???!!!!
ako bude 44 poena,prolazim 100%!!! XD.gif
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pyost
post Feb 11 2007, 03:18 PM
Post #73


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Veceras su rezultati.. Negde oko 7-8.. Tako su barem rekli profesori unsure.gif


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Laza_91
post Feb 11 2007, 03:22 PM
Post #74





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Tako je rekla Chalukovićka,jer

ima 8 profesora i više od 200 učenika,tako da.......
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maxydelanoche
post Feb 11 2007, 03:48 PM
Post #75





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Pa ja koliko sam skontala po resenju, sustina je da se senka krece istom ugaonom brzinom kao i konj, pa onda imas v=omega*r*sqrt(2), a to je ta tangencijalna brzina i ujedno ti je to jedna komponenta ove brzine senke na samom zidu. A brzinu senke po zidu onda dobijes lako...

Bar sam ja tako skonatal resenje koje su oni okacili... XD.gif A cula sam da ste svi radili na razne uvrnute i komplikovane nacine, takoreci, matematicki iscrpne...


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Mi znamo sta se desava sa ljudima koji zastanu nasred puta. Bivaju pregazeni.
Nista nije nemoguce. Za nemoguce je samo potrebno malo vise vremena.

I'm doing the best I ever did, I'm doing the best that I can.

www.viva-fizika.org
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Iva
post Feb 11 2007, 03:54 PM
Post #76





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Lol.
Ja sam lepo izracunala onu jednu komponentu XD.gif mogli su da mi daju na to poene... ali..


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Puzzler
post Feb 11 2007, 04:08 PM
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Ja sam u petom dobio 40 {\frac {km}{h}} wacko.gif

Ispravljam se, jer nisam lepo pročitao podatke...

I ja sam dobio 2*v, ali tako što sam ubacio {\Delta}t=10^{-6} i R=1 m.

Da li bi to priznali???

This post has been edited by Puzzler: Feb 11 2007, 04:12 PM


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Puzzler
post Feb 11 2007, 04:35 PM
Post #78





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Zapravo, ono što sam dobio je


v{\prim}=(tg({\frac {\pi}{4}}+{\frac {v*{\Delta}t}{R})-1)*{\frac {R}{{\Delta}t}}

Pa kad se ubace one vrednosti odgore i vrednost za v, dobije se 40.
Koliko bi mi poena dali???

Eh, mogao sam imati 100... sad.gif
Ali nema veze tongue.gif


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Iva
post Feb 11 2007, 04:39 PM
Post #79





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Lepo sam ti rekla wink.gif


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Laza_91
post Feb 11 2007, 06:24 PM
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90 poena....Jupiiiiiiiiiiiiiiii!!!!!
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